SQL AVG with a subquery. In what city do we have the most employees? Display depart numbers and total number of employees working in each department SQL Query Solution. If multiple employees having the highest salary in the same department then I need the get oldest employee details(who joined first in … Copy and paste your code into your assignment and include a screenshot of your result set in your … Display job ID, number of employees, sum of salary of each … For example, we can use the AVG function to calculate the average salary of employees in each department, and apply the AVG function one more time to calculate the average … The following Query count the total number of employees present in each department, their sales amount, and total annual salaries. 1. Answer: SELECT DEPARTMENT_ID, COUNT (EMPLOYEE_ID) FROM EMPLOYEES GROUP BY DEPARTMENT_ID; Result: Posted by Prosen Ghosh at 08:51. Write a SQL query that will return all the unique department numbers that are represented in the EMPLOYEE table, ordered by department number. The SUM() function returns the total sum of a numeric column. The AVG() function returns the average value of a numeric column. Include the deptno column in your SQL query. Twitter Interview Online Test SQL A company uses 2 data tables, Employee and Department, to store data about its employees and departments. Type ----- ----- ----- EMPLOYEE_ID NOT NULL NUMBER(6) FIRST_NAME VARCHAR2(20) LAST_NAME NOT NULL VARCHAR2(25) EMAIL NOT NULL VARCHAR2(25) PHONE_NUMBER VARCHAR2(20) HIRE_DATE NOT NULL DATE JOB_ID NOT NULL VARCHAR2(10) SALARY NUMBER… use Company; select Dname, COUNT (*) Number_Of_Employee: from DEPARTMENT, EMPLOYEE: where Dno = Dnumber: group by Dname: having AVG … Which query will return the minimum salary in each department? Could you please help me to get the highest salary for each department. Write an SQL query to print the name of employees having the highest salary in each department. Something like this should do SQL> select * 2 from scott.emp e 3 where not exists 4 ( select null 5 from scott.emp 6 where deptno = e.deptno 7 and sal > e.sal ); EMPNO ENAME JOB MGR HIREDATE SAL COMM … Need to Pass employee Id and get total number of employees working under the manager whose employee id is passed in SQL. Display department number and its employee count if it has more than 4 employees: 2.6.7. List the employees whose salary is higher than the average salary with self join COUNT() Syntax. ... --57. SQL> DESC employees Name Null? The SQL COUNT(), AVG() and SUM() Functions. The COUNT() function returns the number of rows that matches a specified criterion. List department who has more than 4 employee born after 1960: 2.6.8. For this SQL server Derived Table example, we are using Inner Join to get a column from both Employees and Department tables. We can apply AVG function multiple times in a single SQL statement to calculate the average value of a set of average values. Write a SQL query to return the employee number, name and salary of all ‘CLERK’ who work in Department 10. SELECT COUNT(column_name) Display the employees who are working in “Oxford” (should use sub query) SELECT EMPLOYEES.EMPLOYEE_ID,EMPLOYEES.FIRST_NAME,EMPLOYEES.LAST_N AME,LOCATIONS.CITY FROM EMPLOYEES . Write a query to print the respective Department Name and number of employees for all departments in the Department table (even unstaffed ones). 25. 2.6.6. Employees Per Department. In this example you will be grouping by deptno. Out should be like this : - EmplD NoofEmployees 1234 10 2562 25 Where 10 & 25 is actually the total number of employees working under the manager of EmplD 1234 and 2562 … For each department whose average employee salasy is more than $30,000, retrive the department name and the number of employees working for that department. 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